-4.9t^2+27t+2.4=1

Solution for -4.9t^2+27t+2.4=1 equation:

-4.9t^2+27t+2.4=1

We move all terms to the left:

-4.9t^2+27t+2.4-(1)=0

We add all the numbers together, and all the variables

-4.9t^2+27t+1.4=0

a = -4.9; b = 27; c = +1.4;
Δ = b2-4ac
Δ = 272-4·(-4.9)·1.4
Δ = 756.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{756.44}}{2*-4.9}=\frac{-27-\sqrt{756.44}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{756.44}}{2*-4.9}=\frac{-27+\sqrt{756.44}}{-9.8}
$